python 2.7 - Groupby match into list of lists -


i have 2 lists have matching elements. example:

l1 = [a, b] l2 = [1_a, i_x, i_y, 2_a, x_b, y_b, z_b]

i wish group matching factors new list following:

match_grouplist = [[1_a, 2_a],[x_b, y_b, z_b]]

i tried,

pull = []; tmp = []    entry in range(len(l1)):         spp = l[entry]         ele in l2:             if ele.split("_")[1] == spp:                 tmp.append(ele)           pull.extend(tmp)

it produces list. can suggest how make list of list ?

thanks in advance,

ap

here solution using list comprehensions :

[ [e2 e2 in l2 if e2.endswith('_'+e1)] e1 in l1 ]

this means each element e1 of l1 elements of l2 end _e1, , return it.

the result [['1_a', '2_a'], ['x_b', 'y_b', 'z_b']]


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