mysql - Sequelize join multiples fields - multiples tables -


can convert query below sequelize? set simple example illustrate idea, compare same table more 1 table. tablec.field_4 = tableb.field_4 , tablec.field_1 = tablea.field_1 , ( tablea.field_8 = 1 or tablec.field_4 not null )

var tablea = sequelize.define('tablea',  field_1 : {    type : sequelize.bigint, primarykey : true, autoincrement : true },  field_2 : {     type : sequelize.bigint, },  field_3 : {    type : sequelize.bigint(4),    references : {        model : 'tabled',       key : 'field_3'    } },  field_8 : { type : sequelize.boolean, allownull : false,     defaultvalue : true }, {      tablename : 'tablea' } );    var tableb = sequelize.define('tableb', {  field_4 : { type : sequelize.bigint(4), primarykey : true, autoincrement : true },  field_3 : {     type : sequelize.bigint(4),     references : {         model : 'tabled',         key : 'field_3'     },     allownull : false },  field_5 : {     type : sequelize.string(255),     unique : true,     allownull : false },  field_6 : {     type : sequelize.string },  field_7 : {     type : sequelize.bigint,     allownull : false },  {        tablename : 'tableb' } );    var tablec = sequelize.define('tablec', {  field_4: {     type: sequelize.bigint(4),     primarykey: true     references: {     model: 'tableb',      key: 'field_4'      } },  field_1: {     type: sequelize.bigint,     primarykey: true     references: {     model: 'tablea',     key: 'field_1'      } },  { tablename: 'tablec' } );  select     *     tablea join tableb on     tableb.field_3 = tablea.field_3 left join tablec on     tablec.field_4 = tableb.field_4     , tablec.field_1 = tablea.field_1     (         tablea.field_8 = 1         or tablec.field_4 not null     )     , tableb.field_7 = 10     , tablea.field_2 = 1036


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