html - How to change color of button in active state using inline CSS? -


is there way change background color and/or border color of button when in active state (i.e. clicked) using inline css?

<button class="btn btn-xs btn-primary btn-inverse dropdown-toggle" type="button" data-toggle="dropdown" style="margin-top: 12px; background-color: rgba(0, 0, 0, 0); border-color:rgba(0, 0, 0, 0); margin-right:20px">

something when button clicked?

considering css :active css pseudo-class , not dom property or attribute can't have inline equivalent that.

but, if in case, click event valid alternative, can that...

<script>    function togglebg(element, color) {      if(!color) {        color = element.dataset.normalcolor;      } else {        element.dataset.normalcolor = element.style.backgroundcolor;      }        element.style.backgroundcolor = color;    }  </script>    <button onmousedown="togglebg(this,'red')" onmouseup="togglebg(this)">red on press</button>

just note, inline-styling or inline-javascript isn't practice, if can, use css:

<style>    button:active { background: red; }  </style>    <button>red when active</button>


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