python - PyQT4: why does QDialog returns from exec_() when setVisible(false) -


i'm using python 2.7 , pyqt4.

i want hide modal qdialog instance , later on show again. however, when dialog.setvisible(false) called (e.g., using qtimer), dialog.exec_() call returns (with qdialog.rejected return value).

however, according http://pyqt.sourceforge.net/docs/pyqt4/qdialog.html#exec, _exec() call should block until user closes dialog.

is there way hide dialog without _exec() returning?

#!/usr/bin/env python # -*- coding: utf-8 -*-  import sys import os pyqt4 import qtgui, qtcore   class mydialog(qtgui.qdialog):     def __init__(self, parent):         qtgui.qdialog.__init__(self, parent)      def closeevent(self, qcloseevent):         print "close event"      def hideevent(self, qhideevent):         print "hide event"   class mywindow(qtgui.qmainwindow):     def __init__(self):         qtgui.qmainwindow.__init__(self)         self.setwindowtitle("main window")         button = qtgui.qpushbutton("press me", self)         button.clicked.connect(self.run_dialog)      def run_dialog(self):         self.dialog = mydialog(self)         self.dialog.setmodal(true)         self.dialog.show()         qtcore.qtimer.singleshot(1000, self.hide_dialog)         status = self.dialog.exec_()         print "dialog exited status {}".format(status), "::", qtgui.qdialog.accepted, qtgui.qdialog.rejected      def hide_dialog(self):         self.dialog.setvisible(false)         # self.dialog.sethidden(true)   if __name__ == '__main__':     app = qtgui.qapplication([])     w = mywindow()     w.show()     sys.exit(app.exec_())

ps1: code prints following output:

hide event dialog exited status 0 :: 1 0

(the close event not called).

ps2: context, i'm trying implement systemtrayicon allows hide , restore qmainwindow (this part fine) , possibly modal qdialog without closing dialog.

thanks!

you can bypass normal behaviour of qdialog.setvisible (which implicitly closes dialog), calling base-class method instead:

    def hide_dialog(self):         # self.dialog.setvisible(false)         qtgui.qwidget.setvisible(self.dialog, false)

however, might preferrable connect dialog's finished() signal, rather using exec(), , explicitly reject() dialog in closeevent.

#!/usr/bin/env python # -*- coding: utf-8 -*-  import sys import os pyqt4 import qtgui, qtcore  class mydialog(qtgui.qdialog):     def __init__(self, parent):         qtgui.qdialog.__init__(self, parent)         layout = qtgui.qhboxlayout(self)         title, slot in ('ok', self.accept), ('cancel', self.reject):             button = qtgui.qpushbutton(title)             button.clicked.connect(slot)             layout.addwidget(button)      def closeevent(self, qcloseevent):         print "close event"         self.reject()      def hideevent(self, qhideevent):         print "hide event"  class mywindow(qtgui.qmainwindow):     def __init__(self):         qtgui.qmainwindow.__init__(self)         self.setwindowtitle("main window")         button = qtgui.qpushbutton("press me", self)         button.clicked.connect(self.run_dialog)      def run_dialog(self):         self.dialog = mydialog(self)         self.dialog.finished.connect(self.dialog_finished)         self.dialog.setmodal(true)         self.dialog.show()         qtcore.qtimer.singleshot(3000, self.dialog.hide)      def dialog_finished(self, status):         print "dialog exited status:", status  if __name__ == '__main__':      app = qtgui.qapplication([])     w = mywindow()     w.show()     sys.exit(app.exec_())

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